Evaluate the integral by parts

Question

upper bound = 1 lower bound = 0

-5y/e²y

Answer 1

The integrand makes no sense: Is it supposed to be e^2y?

I use the acronym "Lit Pet" to pick the u (Log, Inverse Trig, Power, Exponential, Trig)

If so you say u= -5y and dv= e^2ydy (du = -5 and v = (e^2y/2)

You can now solve integral of udv = uv - integral of vdu evaluated from 0 to 1