Since 1/tan(x) = cot x, the integrand is 7 csc2(x) * csc(x) cot(x); via the u-substitution u = csc x, du = -csc x cot x dx, we obtain
∫ 7 csc2(x) * csc(x) cot(x) dx = ∫ 7 u2 (-du) = -7 ∫ u2 du = -7u3/3 + C = -(7/3)csc3(x) + C
Ayah M.
asked 10/19/22Find the integral of 7 csc3(x) / tan(x) dx
Since 1/tan(x) = cot x, the integrand is 7 csc2(x) * csc(x) cot(x); via the u-substitution u = csc x, du = -csc x cot x dx, we obtain
∫ 7 csc2(x) * csc(x) cot(x) dx = ∫ 7 u2 (-du) = -7 ∫ u2 du = -7u3/3 + C = -(7/3)csc3(x) + C
Richard C. answered 10/19/22
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