Rice L.
asked 10/16/22Can someone help me on this question. I don’t get how I’m supposed to proceed because one of the equations equals 0/0
Define a function f-> R -> R as follows, where c is a constant:
f(x)= ((square root of (x^2 + 5x) -6)/ (x^2-9x+20) if x<4
And
(x^2-cx-9)/(2x+4) if x >= 4
What value of c is needed to make f a continuos function
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1 Expert Answer
Use l'Hospital's rule on the expression to the left of 4...to get a removable discontinuity with value = -13/12.
Then set f(4)=-13/12 to find c so that f will be continuous.
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Rice L.
In case it’s not clear, the square root is only over x^2 and 5x. The minus 6 is outside of the square root10/16/22