Rice L.

asked • 10/16/22

Can someone help me on this question. I don’t get how I’m supposed to proceed because one of the equations equals 0/0

Define a function f-> R -> R as follows, where c is a constant:


f(x)= ((square root of (x^2 + 5x) -6)/ (x^2-9x+20) if x<4

And

(x^2-cx-9)/(2x+4) if x >= 4


What value of c is needed to make f a continuos function

Rice L.

In case it’s not clear, the square root is only over x^2 and 5x. The minus 6 is outside of the square root
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10/16/22

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