Standard Normal Distribution

Question

P(x<1.86)

Answer 1

If the random variable x is characterized by a standard normal distribution, it follows that x is a continuous random variable, with

x ~ N(µ = 0 , σ = 1);

thus,

P(x < 1.86) = P(x ≤ 1.86) = F(1.86)

= normalcdf(-∞, 1.86, 0 , 1)

= 0.96856

(here, normalcdf() denotes the same function as that on a TI calculator and thus follows the same notation as the function on the calculator).

Hope that helps!