Raymond B. answered 10/12/22
Math, microeconomics or criminal justice
170 north moving closer at 10 m/sec
150 west moving closer at 15 m/sec
after 2 seconds
they are 170-2(10) = 150 north
and 150-2(15) = 120 west
construct a right triangle with altitude 150 and base 120, the hypotenuse, the distance between them, = h = sqr(150^2+120^2) = 250 meters
h^2 = a^2 + b^2
take the derivative,
this is a related rates problem, a subtopic,
found in textbooks under the topic "derivatives"
2hh' = 2aa' +2bb'
divide by 2h
h'= (aa'+bb')/h
plug in the values, a=150, a'=-10, b=120, b'=-15, h=250, solve for h'
h' = (-1500-1800)/250
= -3300/250 = -330/25
h' = -13.2 m/sec
= rate of change of distance between the two cars after 2 seconds