
Yefim S. answered 10/12/22
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y = (x - 1)2; x = (y - 1)2; y = 1 + √x, x ≥ 0
f-1(x) = 1 + √x, x ≥ 0
William A.
asked 10/12/22f(x)=(x-1)^2, [1, infinity)
I am looking for the inverse.
f^1(x)=_____________________
Yefim S. answered 10/12/22
Math Tutor with Experience
y = (x - 1)2; x = (y - 1)2; y = 1 + √x, x ≥ 0
f-1(x) = 1 + √x, x ≥ 0
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