The slope is (5/7)ln47
The point is (7,ln57)
Now you have a slope and a point.
Can you write down the point-slope form of the equation of the tangent?
Tanner S.
asked 10/09/22Find the equation of the line tangent to the graph of f(X)=(lnx)^5 at x=7
The slope is (5/7)ln47
The point is (7,ln57)
Now you have a slope and a point.
Can you write down the point-slope form of the equation of the tangent?
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