
Arcenis R. answered 10/07/22
Data scientist and economist | Expert in R | Patient tutor
The first thing to do here is calculate how many combinations of 3 students we can get from a group of 24 students by using the combination formula:
C(n, r) = n! / ((n - r)! × r!)
There are C(24, 3) possible combinations of 3 students out of the total of 24
C(24, 3) = 24! / ((24 - 3)! × 3!) = 2024
Out of our 2024 possible combinations of 3 students out of 24, only 1 combination has all 3 siblings in it. The probability that all 3 siblings are selected in the same group of 3 is 1 / 2024 = 0.000494. The question says there are 8 homes, but it doesn't state that it matters which of they 8 homes they get placed in, so the probability remains 0.000494 or 0.0494%.