Derivaitve Question of Logs

Question

Letf(x)=(ln⁡x)2

f′(x)= 

f′(e4)= 

Answer 1

Assuming the final two is not an exponent, we have:

f'(x) = 2/x (f'(2y) = 2(f'(y)) and the log rule: f(lnx) = 1/x

Assuming the 4 is not an exponent, we have:

f'(e4) = 2/e4 = 1/2e

I suspect both constants are exponents, in which case:

f'(x) = 2ln(x)/x (use the Power Rule and the Chain Rule)

f'(e^4) = 0.146525

I would be happy to answer again if I have misinterpreted your question :)