f(x)=sec(x−20)+sec(2x^5). Find the derivative

Answer 1

If f(u) = secu, then f'(u) = secutanu u'

So, for f(x) = sec(x-20) + sec(2x⁵), f'(x) = sec(x-20)tan(x-20) + 10x⁴sec(2x⁵)tan(2x⁵)