Victoria M.

asked • 10/04/22

Find the value of c that makes h (x) continuous at x=3

h(x)=

x^2-2x-3/x^2-5x+6 x doesn't =3

x^2-cx-2 x=3

William W.

Is h(x) a piecewise function? If so, you are missing the domain constraints. If not, what is the relationship between "x^2-2x-3/x^2-5x+6" and "x^2-cx-2"?
Report

10/04/22

Victoria M.

It's a limit
Report

10/04/22

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