Issac O. answered 10/03/22
M.S. in mathematics, and four years in a Ph.D. in mathematics.
I'll do part (a).
We only need to check A-1+B-1 is a one-sided inverse of the RHS. So the following calculation is enough:
(A-1+B-1)(A(A+B)-1B)
= A-1A(A+B)-1B+B-1A(A+B)-1B
= (A+B)-1B+B-1A(A+B)-1B
= (I+B-1A)(A+B)-1B
= B-1(A+B)(A+B)-1B
= I