Given that, y=1/(3x-2)^2. Find the value of dy/dx

Answer 1

Rewrite as y = (3x-2)^-2, then use the power rule, followed by chain rule.

y'=-2(3x-2)^-3(3) = -6/(3x-2)³

Check out this Desmos graph for confirmation:

desmos.com/calculator/htp80bqm70

Note that the graphs of f'(x) and g(x) are identical.