Roman C. answered 09/27/22
Masters of Education Graduate with Mathematics Expertise
A(A-1 + B-1)B(A + B)-1
= (AA-1 + AB-1)B(A + B)-1 (Left-Distributivity)
= (In + AB-1)B(A + B)-1 (Inverses)
= (InB + AB-1B)(A + B)-1 (Right-Distributivity)
= (InB + AIn)(A + B)-1 (Inverses)
= (B + A)(A + B)-1 (Identity)
= (A + B)(A + B)-1 (Commutativity)
= In (Inverses)