Mark M. answered 09/27/22
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
f(x) = 3x2 - 9
f'(x) = 6x Slope of tangent line = f'(-1) = -6
Equation of tangent line is y - (-6) = -6[x - (-1)]
Simplify to get y = -6x - 12
Lauren H.
asked 09/27/22Consider the following equation and point.
f(x) = 3x2 − 9, (−1, −6)
Find an equation of the tangent line to the graph of f at the given point.
Mark M. answered 09/27/22
Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
f(x) = 3x2 - 9
f'(x) = 6x Slope of tangent line = f'(-1) = -6
Equation of tangent line is y - (-6) = -6[x - (-1)]
Simplify to get y = -6x - 12
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