
Dayv O. answered 09/25/22
Caring Super Enthusiastic Knowledgeable Calculus Tutor
f'(x)=5-7x-2
equals zero
x=+/-√(7/5)
f''(x)=14x-3
when x>0, f''(x)>0, and critical point is a minimum
when x<0, f''(x)<0, and critical point is a maximum
Nikolas H.
asked 09/25/22The function f(x)=5x+7x−1 has one local minimum and one local maximum.
This function has a local maximum at x= with value
and a local minimum at x= with value
Dayv O. answered 09/25/22
Caring Super Enthusiastic Knowledgeable Calculus Tutor
f'(x)=5-7x-2
equals zero
x=+/-√(7/5)
f''(x)=14x-3
when x>0, f''(x)>0, and critical point is a minimum
when x<0, f''(x)<0, and critical point is a maximum
I'm guessing there is a mistake in what you wrote. Do you perhaps mean to have a cube on the leading x? I would guess that there is a square on the leading x but then the resulting function would not have both a local max and local min.
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Nikolas H.
There is a mistake. It should say f(x)=5x+7x^-109/25/22