Travis M. answered • 05/12/15

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Part A:

First, convert molarity to moles by multiplying by the volume:

0.293 M AgNO

_{3}= (0.293 moles AgNO_{3})/1 L x 1.19 L = 0.349 moles AgNO_{3}We are only interested in AgCl, not AgNO

_{3}. We convert moles of silver nitrate to moles of silver chloride using the balanced equation. This is a 1:1 conversion:0.349 moles AgNO

_{3}x (1 mole AgCl)/(1 mole AgNO_{3}) = 0.349 moles AgClTo get mass from moles, we multiply by the molar mass:

0.349 moles AgCl x (143.32 g/mol) =

**50.0 g AgCl**The appropriate unit for mass is, of course, grams.

Part B:

Use the moles of AgNO

_{3}from Part A. Then use the balanced equation to convert from moles of silver nitrate to moles of potassium chloride:0.349 moles AgNO

_{3}x (1 mole KCl)/(1 mole AgNO_{3}) = 0.349 moles KClConcentration units are molarity, M. This is equal to moles/Liter. We were told that 3.47 L were required. Now we just plug in the numbers.

M = (0.349 moles KCl)/(3.47 L) =

**0.101 M**