find the values of x in the interval [o,2pi] that satisfies the equation 8sin^2(x)=4

Answer 1

8 sin² x = 4

sin² x = 1/2

sin x = ±√2 / 2

Can you locate on a unit circle and answer?

Answer 2

1- cos(2x) = 1; cos(2x) = 0; 2x = π/2, 3π/2, 5π/2; 7π/2; x = π/4, 3π/4, 5π/4, 7π/4