Where on the interval [0,pi/5] is the function f(x)= (2x+3)/(cos5x) continous

Answer 1

pi/5 = 180/5 = 36 degrees

f(x) = (2x+3)/cos5x

It's discontinuous for any value of x that makes cos5x = 0

5x = cos^-1(0)

5x = pi/2 or 3pi/2

x = pi/10 or 3pi/10

x = 180/10= 18 degrees

ignore 3(180)/10= 480/10 = 48 degrees as it's >36 degrees> pi/5 radians

f(x) is continuous for the intervals [0,pi/10) U (pi/10, pi/5]