Tiffany K. answered 08/29/22
experienced tutor for math and sciences who loves a challenge
f(2) = 2, f′(2) = 1, g(2) = 3 and g′(2) = 4
F(x) = f(x)*g(x)
Using the product rule
F'(x) = f'(x)*g(x) + f(x)*g'(x)
F'(2) = f'(2)*g(2) + f(2)*g'(2)
F'(2) = 1*3 + 2*4 = 3+8
= 11
F(x) = f(x)/g(x)
Using the quotient rule
F'(x) = [f'(x)*g(x) - f(x)*g'(x)]/g(x)2
F'(2) = [f'(2)*g(2)-f(2)*g'(2)]/g(2)2
F'(2) = [1*3-2*4]/32
= -11/9
Aidan M.
Thanks for that, everything was correct except the easy calculation at the end (1*3-2*4) haha08/29/22