please help thanks

Question

The height yy (in feet) of a ball thrown by a child is

y=−114x2+6x+5y=-114x2+6x+5

where xx is the horizontal distance in feet from the point at which the ball is thrown.

(a) How high is the ball when it leaves the child's hand?    feet

(b) What is the maximum height of the ball?    feet

(c) How far from the child does the ball strike the ground?    feet

Answer 1

(a) y = -114(0)² + 6(0) + 5

(b) y' = -228x + x, set equal to zero and determine y

(c) 0 = -114x² + 6x + 6, solve for x, (formula)