Raymond B. answered 08/06/22
Math, microeconomics or criminal justice
5 feet wide 10 feet long
for a total of 20 feet total fencing
any other dimensions require more fencing for an area of 50 feet
area=LW = L(50/L)=50
Perimeter = P = 2(50/L) + L = 100/L+L
take the derivative and set =0
P' = -100/L^2 + 1 = 0
multiply by L^2
L^2 -100 =0
L=10 feet long
W =50/10 = 5 feet wide