Since your lower limit of integration is a constant and the upper limit of integration has a derivative of just "1", then just plug in the "v" into the function behind the integral sign: dy/dv = √(3 + 4v2)
Alysa T.
asked • 08/04/22Integrals Please Helps
Find dy/dv for
y= ∫ v (above) 0 (below) √3+4t2 dt. (dt not in square root)
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Joseph G.
Great answer! Just to add on, it follows the fundamental theory of calculus. We know that the function √3+4t2 is continuous on the interval of 0 to v then we can just plug v into the equation.08/04/22