Raymond B. answered 08/04/22
Math, microeconomics or criminal justice
TR = -2q^2 +600q +600
TC= 3q^2 -200q + 400
Profit, P, = Total Revnue minus Total Cost
= TR-TC =-2q^2 +600q +600 -[3q^2 -200q +400]
-5q^2 +800q -200
P'(q)) = -10q +800 =0
q = 800/10 = 80 = profit maximizing output
MR= -4q +600
MC =6q -200
MR=MC
-4q+600 = 6q-200
10q = 800
q = 80
P=-5q^2 + 800q -200
P(80) =-5(80)^2 +800(80) -200
= -32000 + 64000 -200
= 32000-200
= 31,800 = maximum profit
or you might try a graphical approach
each curve is a parabola, one upward opening, the other downward opening
their difference is another parabola, downward opening
P=-5x^2 + 800x -200
=-5(x^2 -160x + 80^2) -200 +5(80^2)
= -5(x-80)^2 +31,800 which has vertex = maximum = (80,31,800)
TR =-2q^2 +600x +600 is a downward opening parabola
= -2(q^2 -300x + 150^2) + 600 +2(150^2)
= -2(q-150)^2 + 44600
vertex = max = (150,44,600)
TC =3q^2 -200q +400
=3(q^2 -200q/3 + 100^2/3) + 400 -100^2/3
= 3(q-100/3)^2 - 9,800/3
vertex = minimum = (33 1/3, -3,266 2/3)
graph MR and MC. they're two lines
where they intersect is the profit maximizing price and quantity