Yefim S. answered 08/02/22
Math Tutor with Experience
dy/((0.05y + 4000) = dt; ∫dy/(0.05y + 4000) = ∫dt; 20lnI0.05y + 4000I= t + 20lnC; 0.05y + 4000 = Ce0.05t;
y(0) = 100000; 5000 + 4000 = C; C = 9000
y(t) = 180000e0.05t - 80000
Gabe T.
asked 08/02/22Let y(t) represent your bank account balance, in dollars, after t years. Suppose you start with $100000 in the account. Each year the account earns 5% interest, and you deposit $4000 into the account.
This can be modeled with the differential equation:
dy/dt=0.05y+4000
y(0)=100000
Solve this differential equation for y(t)
y(t) =
Yefim S. answered 08/02/22
Math Tutor with Experience
dy/((0.05y + 4000) = dt; ∫dy/(0.05y + 4000) = ∫dt; 20lnI0.05y + 4000I= t + 20lnC; 0.05y + 4000 = Ce0.05t;
y(0) = 100000; 5000 + 4000 = C; C = 9000
y(t) = 180000e0.05t - 80000
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.