Euler's method: yn+1 = yn + h*yn'
In this case y(1.5) = y(1) + .5y'(1) where y'(1) = 2 + 3*1 - 2*y(1)
y(1.5) = 2 + .5(2+3-2*2) = 2.5
Now, do the same thing for the next step using the value at y(1.5), rather than y(1)
Please consider a tutor. Take care.