I don't know why this is calculus, except that you can derive that work = change in kinetic energy = 1/2 mv2
W = integral of (Fdx = ma dx = m(dv/dt)(dx) = mdv (dx/dt) = mvdv) = 1/2 mv2 + C
In this case, it is just a matter of plugging in W = 1/2 mv2 (v initial = 0) in metric units where
8oz*(1lb/16 oz)(1kg/2.2 lbs) and
64 miles/hour * (1610 m/mil) (1 hour/3600s)
Plug into formula and W will be in Joules.