We are going to use the disk method. The body of rotation will be sliced to thin disks perpendicular to the X-axis with the thickness of dx and areas of π y2 .
Thus the volume of each disk is π y2 dx, and we need to integrate over all values of x (inside the 2D shape which is being rotated).
The line x + 2y = 2 crosses the X axis at x = 2, therefore 2 is the upper bound of the integral.
Now we need to solve for y
y = 1 - x/2
The integral will be as follows
from x = 0 to x = 2 Integral of π y2 dx =
from x = 0 to x = 2 Integral of π ( 1 - x/2 )2 dx