Use F = kx to find the spring constant k.
Then W = integral of F dx, the bounds go from 0 to 1.1 ft.
Keep all units in ft and lbs.
Chancellor D.
asked • 07/17/22Finding Work (Calculus 2)
A force of 55 pounds is required to hold a spring that is stretched 0.3 feet beyond it's natural length.
How much work (in foot-pounds) is done when stretching the spring from it's natural length to 1.1 feet beyond it's natural length?
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