First do a little algebra to get y as a function of x as y=(2/3)sqrt(36-x2)
Then make the substitution x=6 sin θ to evaluate the integral.
Find the integral from 0 to 6 which is the area of (1/4) of the ellipse.
Gabe T.
asked 07/15/22Use integration and trigonometric substitution to find the area enclosed by the ellipse: x^2/36 + y^2/16 = 1.
First do a little algebra to get y as a function of x as y=(2/3)sqrt(36-x2)
Then make the substitution x=6 sin θ to evaluate the integral.
Find the integral from 0 to 6 which is the area of (1/4) of the ellipse.
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