The distance traveled is d(t) = ∫0t |v(s)| ds = ∫0t s2e-s ; by integration by parts,
d(t) = s2(-e-s) - (2s)(e-s) + (2)(-e-s)|0t = -t2e-t -2te-t -2e-t - (-2) = 2 - (t2 + 2t + 2)e-t
Gabe T.
asked 07/15/22A particle that moves along a straight line has velocity
v(t)=t^(2)e^(−4t)
meters per second after t seconds. How many meters will it travel during the first t seconds (from time=0 to time=t)?
The distance traveled is d(t) = ∫0t |v(s)| ds = ∫0t s2e-s ; by integration by parts,
d(t) = s2(-e-s) - (2s)(e-s) + (2)(-e-s)|0t = -t2e-t -2te-t -2e-t - (-2) = 2 - (t2 + 2t + 2)e-t
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