Use Part I of the Fundamental Theorem of Calculus to find the derivative of

Question

g'(x)= integral from 6x to 7x of (u+2)/(u-4)

Answer 1

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Answer 2

I think you meant

g(x) = ∫^7x_6x (u+2)/(u-4) du Let f(u) = (u+2)/(u-4)

= ∫^7x_a f(u) du - ∫^6x_a f(u) du Let h(x) = 7x and d(x) = 6x

g'(x) = f(x)h'(x) - f(x)d'(x) = f(x)(7-6) = f(x) = (x+2)/(x-4)