Raymond B. answered 07/01/22
Math, microeconomics or criminal justice
f(x) = 2x^7 -x^5 +5x^3 - 8x + 4
find the 5th derivative
f'v(x) = 7(6)5(4)(2)x^3 = 1680x^3
just work with 2x^7-x^5, ignore the other 3 terms as they drop out by the 5th derivative
f'(x)=14x^6 -5x^4 +
f'(x) = 84x^5 -20x^3 +
f"'(x) = 420x^4 -60x^2 +
f'v(x) = 1680x^3 -120x
fv(x) = 5040x^2 - 120
Lee S.
Thank you!07/01/22