Patrick T. answered 06/28/22
Tutor Specializing in French & Math (up to college Pre-Calculus)
Hello Dwayn,
You would use both the power rule and chain rule. The way I'm doing it below is not the only way, but one I'm most familiar with.
if you set u = ln(x5 - 4), then u' = (derivative of x5 -4) / (x5 -4) = 5x4/(x5 -4)
The original function is f(x)=[ln(x^5-4)]^3 which you could rewrite as u3
To find derivative of u3, we would use the power rule: (u3)' = 3 * u' * u2
So: (u3)' = 3 * 5x4/(x5 -4) * [ln(x5 -4)]^2 = 15 * x4 * [ln(x5 -4)]2 / (x5 -4)