Robin T.
asked • 06/22/22Dice probability
In a game of chutes and latters, suppose you need a 4 to win the game. You are rolling a 6-faced fair die. What is the probability that you will win the gam on the third try?
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2 Answers By Expert Tutors
Patrick F. answered • 06/22/22
Tutor
5
(14)
Inspiring Math Teacher and former Actuary
This is slightly more complicated than it first appears. I've been working on making Math animations with Manim, and used this question for practice.
Please take a look at this video: https://youtu.be/JrHXSn9J1Ts
P(3rd try) = P(not 4) x P(not 4) x P(4) = 5/6 * 5/6 *1/6
Please consider a tutor.
If you are actually asking P(by the 3rd try) = 1-P(no 4, 3 times) = 1 - (5/6)3
Please consider a tutor. Take care.
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Patrick F.
Let's see if I understand the game right. You need 4 exactly to finish and win. If you roll more than 4 then you don't move. If you roll less than than 4 then you move - for example you roll a 1, now you need three on the next roll to win. Let me know, then I can help you arrive at the answer.06/22/22