(a) int from 0 to 4.5 - integral from 3 to 4.5 - integral from 0 to 1.5.
(b)The second integral is - (answer to a) - 6(1.5) + 6(3) (separated integral and evaluated int (-6) = -6x from 3 to 1.5.
Zane B.
asked 06/20/22let ∫04.5f(x)dx=1, ∫01.5f(x)dx=6, ∫34.5ff(x)dx=10
find ∫1.53f(x)dx=
and ∫31.5(1f(x)-6)dx=
(a) int from 0 to 4.5 - integral from 3 to 4.5 - integral from 0 to 1.5.
(b)The second integral is - (answer to a) - 6(1.5) + 6(3) (separated integral and evaluated int (-6) = -6x from 3 to 1.5.
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