Find the equation of the tangent line of the curve at the given point:

Question

g(x)=radx+2 at the point (7,3)

Answer 1

g(x) = √(x+2)

g'(x) = (1/2)(x+2)^-1/2

Slope of tangent line = g'(7) = 1/6

Equation of tangent line is y - 3 = (1/6)(x - 7) or equivalently y = (1/6)x + 11/6

Answer 2

g(x) = x^1/2 + 2

g'(x) = ?

g'(7) = ?, This is slope of tangent line

Use point-slope form from Algebra to determine the equation of the tangent line.