Brian Y. answered 06/06/22
Columbia University Graduate Specializing in Computer Science and Math
Critical points occur where f'(x) = 0 or f'(x) = DNE.
We have
f(x) = (x-2)2+4x-4 = 2x-4+4x-4 = 6x - 8
Thus, we have
f'(x) = 6
Notice that f'(x) is never 0. Hence, f(x) does not have any critical points.