It is given dr/dt = 2 cm/min. When the radius is 8 cm, the volume rate is
dV/dt = 4πr2 dr/dt = 4π(8 cm)2 (2 cm/min) = 512π cm3
Zane B.
asked 05/31/22The radius of a spherical balloon is increasing at a rate of 2 centimeters per minute. How fast is the volume changing, in cubic centimeters per minute, when the radius is 8 centimeters?
Note: The volume of a sphere is given by: V=(4/3)pir^3
It is given dr/dt = 2 cm/min. When the radius is 8 cm, the volume rate is
dV/dt = 4πr2 dr/dt = 4π(8 cm)2 (2 cm/min) = 512π cm3
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