Salvador S. answered 10/28/25
Professional Math Tutor | Basic Math through Linear Algebra
If I understood your question correctly, we need to find a linear operator T: ℝ² → ℝ² such that T(1,1) = (2,2) and T(2,1) = (4,5).
Since T is a linear operator, it has the form:
- T(x,y) = (ax + by, cx + dy) for some constants a, b, c, and d.
Finding the constants:
Using the condition T(1,1) = (2,2):
- a(1) + b(1) = 2 → a + b = 2
- c(1) + d(1) = 2 → c + d = 2
Using the condition T(2,1) = (4,5):
- a(2) + b(1) = 4 → 2a + b = 4
- c(2) + d(1) = 5 → 2c + d = 5
Solving for a and b: From 2a + b = 4 and a + b = 2, subtract the second from the first: a = 2
Substitute back: 2 + b = 2, so b = 0
Solving for c and d: From 2c + d = 5 and c + d = 2, subtract the second from the first: c = 3
Substituting back we get: 3 + d = 2, so d = -1
Answer:
T(x,y) = (2x, 3x - y)
Verification:
- T(1,1) = (2·1, 3·1 - 1) = (2, 2) ✓
- T(2,1) = (2·2, 3·2 - 1) = (4, 5) ✓
Sorry its a bit late but maybe it should have been tagged as Linear Algebra. Hope you did well in your class. Cheers!