Raymond B. answered 05/25/22
Tutor
5
(2)
Math, microeconomics or criminal justice
as h approaches zero, the limit = -12
f(x) = x^2
f'(x) = 2x
f'(-6) = 2(-6) = -12
f(x+h)x-f(x) = x^2 +2xh +h^2 -x^2 = 2xh+h^2
(2xh +h^2)/h = 2x + h
limit of 2x+h as h approaches zero = 2x
when x = -6, the limit = 2(-6) = -12