you have a bag of 17 marbles four are blue 6 are green 2 are red 5 are yellow what is the probablit of drawing a green marble keeping it then drawing a yellow marble

Answer 1

Event A = draw green marble on 1st draw

Event B = draw yellow marble on 2nd draw

Since sampling without replacement A and B are dependent events so:

P(A and B) = P(A) * P(B|A)

6 green marbles out of 17 so P(A) = 6/17

that leaves 16 marbles, of which 5 are yellow, so P(B|A) = 5/16

P(A and B) = 6/17 * 5/16 = 30/272 = 15/136