P(male smoker)=51/(51+459) or 51/510 --> 1/10
P(female smoker)=60/(540 + 60) or 60/600 --> 1/10
P(male and female smoker)=P(male smoker)*P(female smoker) or 1/10 * 1/10 --> 1/100 --> 0.01
Travien S.
asked 05/10/22At a local college, 51 of the male students are smokers and 459 are non-smokers. Of the female students, 60
are smokers and 540 are non-smokers. A male student and a female student from the college are randomly selected for a survey. What is the probability that both are smokers?
Do not round your answer.
P(male smoker)=51/(51+459) or 51/510 --> 1/10
P(female smoker)=60/(540 + 60) or 60/600 --> 1/10
P(male and female smoker)=P(male smoker)*P(female smoker) or 1/10 * 1/10 --> 1/100 --> 0.01
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