Integrate this problem

Question

∫ x⁴(x⁵+3)⁷ dx

Answer 1

Let u = x⁵+3. Then du = 5x⁴dx. So, x⁴dx = (1/5)du.

The given integral is then equivalent to (1/5) ∫u⁷du = (1/40)u⁸ + C = (1/40)(x⁵+3)⁸ + C