find the plane region between

Question

f(y)= y² and the y-axis from y= 0 to y= 3

Answer 1

x = y^2

intergral = y^3/3

evaluate from y = 0 to 3

= 3^3/3 = 9

Area between the function and the y-axis = 9

or

y = sqrx

integral is

x^(3/2)/3/2 = (2/3)xsqrx

evaluated at x = 0 to 9

= (2/3)9(3) = 18

3x9 - 18 = 27 -18 = 9

Area = 9