Raymond B. answered 05/07/22
Math, microeconomics or criminal justice
f(x) = 11-3x^2
f(2.1) = 11-3(2.1)^2 = 11 -3(4.41) + 11-13.23 = -2.23
f(2.1) = -2.23 exactly
the linear approximation is
L(x) = f(a)+f'(a)(x-a)
L(2.1) = f(2) +(-12)(2.1-2)
= -1 -1.2
= -2.2= the linear approximation
-2.2 is close to -2.23
it's off by 0.03
0.03/2.23 = .013453 = 1.345% error approximately, rounded to 3 decimal places
graphically, f(x) is a downward opening parabola
the point (2.1, -2.23) is where a tangent line touches the parabola
with the tangent line as y=-12x +23