
Yefim S. answered 04/28/22
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∫x2/(2x - 3)dx = ∫[x/2 + 3/4 + 9/4·1/(2x - 3)] = x2/4 + 3/4x + 9/8lnI2x - 3I + C
Yefim S. answered 04/28/22
Math Tutor with Experience
∫x2/(2x - 3)dx = ∫[x/2 + 3/4 + 9/4·1/(2x - 3)] = x2/4 + 3/4x + 9/8lnI2x - 3I + C
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