Raymond B. answered 04/27/22
Math, microeconomics or criminal justice
2x/(5x+1)
integral = [-2(ln|5x+1| -5x)]/25
u=5x+1, du=5
-5x = 1-u
integral = [-2(ln|u| -u]/25 + c
where c = an unknown constant
2x/(5x+1)dx
=2[(u-1)/5]/u)du/5
=(2/5)(u-1)/u)du
= (-2/25)((1/u-1)
integral = (-2/25)(ln|u|-u) + c