Raymond B. answered 04/27/22
Math, microeconomics or criminal justice
u= 5x+4
du =5dx
dx =du/5
integral of dx/(5x+4)^3
=integral of du/5u^3
=(1/5)integral of (u^-3)du
=(1/5)(u^-2)/-2 + c where c = an unknown constant
= -1/10u^2 +c = the antiderivative in terms of u
= -1/10(5x+4)^2 + c = the antiderivative in terms of x
check the answer by taking the derivative
[-1/10u^2]'
=[-(1/10)u^-2]'
=(-2)(-1/10)u^-3
= 1/5u^3
or
[-1/10(5x+4)2]'
=[(-1/10)(5x+4)^-2]'
=-2(-1/10)(5)(5x+4)^-3
= (10/10)(1/(5x+4)^3
= 1/(5x+4)^3