Use Newton's method to approximate the given number correct to eight decimal places. 6sqrt(47)

Answer 1

For this you want to create a function that you can use Newton's method to evaluate.

Let x = 6√47

Then x²=36(47)

Let f(x) = x²-(36)(47) (you can go ahead and multiply 36(47) if you want), Finding the root of that function will be the same as evaluating 6√47 -- imagine solving that equation for x,

Start with an initial value of x₁=40 (since √47 is between 6 and 7)

Look at earlier answers to the questions you have posed on how to invoke Newton's Method.

Check your work here:

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